Results on finite dimensionality and algebraicity of intermediate fields. #
Turn an algebraic subalgebra into an intermediate field, Subalgebra.IsAlgebraic version.
Equations
- hS.toIntermediateField = { toSubalgebra := S, inv_mem' := ⋯ }
Instances For
Turn an algebraic subalgebra into an intermediate field, Algebra.IsAlgebraic version.
Equations
- Algebra.IsAlgebraic.toIntermediateField S = ⋯.toIntermediateField
Instances For
The algebraic closure of a field K in an extension L, the subalgebra integralClosure K L
upgraded to an intermediate field (when K and L are both fields).
Equations
- algebraicClosure = Algebra.IsAlgebraic.toIntermediateField (integralClosure K L)
Instances For
Equations
- ⋯ = ⋯
Equations
- ⋯ = ⋯
If F ≤ E are two intermediate fields of L / K such that [E : K] ≤ [F : K] are finite,
then F = E.
If F ≤ E are two intermediate fields of L / K such that [F : K] = [E : K] are finite,
then F = E.
If F ≤ E are two intermediate fields of L / K such that [L : F] ≤ [L : E] are finite,
then F = E.
If F ≤ E are two intermediate fields of L / K such that [L : F] = [L : E] are finite,
then F = E.
If L/K is algebraic, the K-subalgebras of L are all fields.
Equations
- One or more equations did not get rendered due to their size.